In an ac circult, the current is given by 1 = 4 sin (100 + 30") ampere. The current becomes maximum first time (after t = 0) t equal to - (1) (1/200) sec (2) 300 sec (3) (1/50) sec (4) (1/300) sec
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An ac circuit, the current is given by i=4 sin (100 πt+ .30^∘) ampere. The current becomes maximu... - YouTube
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In an AC circuit , the current is given by 1 = 4 sin(100 pi + 300) ampere. The current becomes maximum first time (after t = 0) at t equal to
An ac circuit, the current is given byi-4 sin (100rct + 30º) ampere. The current becomes maximum first time (after t=0) t equal to - (A)(1/200) sec (B)(1/300) sec (C)(1/50) sec (
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In an AC circuit , the current is given by 1 = 4 sin(100 pi + 300) ampere. The current becomes maximum first time (after t = 0) at t equal to
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An ac circuit, the current is given by i= 4 sin (100 rct +30°) ampere. The current becomes maximum first time (after t= 0) t equal to - (A) (1/200) sec (B) (
Triangle ABC has right angle at C, BAC<45 degrees, and AB = 4. Point P is on AB is chosen such that APC<2*ACP and CP=1. The ratio AP/BP can be represented in
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